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File: 124975086811.gif-(177.34KB, 700x880, 122240579861.gif)
3509 No. 3509 Stickied hide watch expand quickreply   [Reply]
/calc/ now has an IRC channel where everyone can get their math on in real time.
Feel free to join our game of multiplayer notepad at #calc on irc.99chan.org
3 posts omitted. Click Reply to view.
>> No. 3779
So is this the place to hang out when having math in school?


No. 2379 Stickied hide watch expand quickreply   [Reply]
Hello calc. Use the red link under the banner to launch the latex editor. It has many advanced functions and it's output can be quickly saved as a .gif or .png for posting to this board.
10 posts and 2 images omitted. Click Reply to view.
>> No. 2971
7


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3744 No. 3744 hide watch expand quickreply   [Reply]
X^0=1
X=0
therefore,
0^0=1
2 posts and 1 image omitted. Click Reply to view.
>> No. 3747
hold it. 0^0 = 0 because you forgot the rule about 0: if 0 is ^x it still becomes zero.
That is, 0^x = 0
we replace x with 0
0^0 = 0
my moot point.
>> No. 3748
File: 125403828392.gif-(2.10KB, 299x141, CodeCogsEqn.gif)
3748
>>3747
if you were right, Taylor series wouldn't work that well then (see pic)

http://mathforum.org/dr.math/faq/faq.0.to.0.power.html
>> No. 3943
let's look at the function f(x,y)=x^y = exp[y*ln(x)] . Does it have a limit as we approach the origin?


File: 125861785696.jpg-(50.48KB, 594x397, Probability.jpg)
3938 No. 3938 hide watch quickreply   [Reply]
So, say you have a 50/50 chance of something happening, whatever it is. Now, say you get the same result with this, for a thousand times. Wouldn't you have more chances, as time passes by, to get the other result ? While still it being 50/50 ?
MY MIND IS CONFUSED
>> No. 3939
Independent variables, meaning that one experiment does not rely upon the result of the other.
>> No. 3942
if you have a fair coin, no matter how much you flip it you'll always have 50% chance of heads and 50% chance of tails


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3940 No. 3940 hide watch quickreply   [Reply]
My mathematics teacher gonna get retired by dec...

i told him i'd give him the most complicated sum i could think of before retirement...any suggestions?


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3312 No. 3312 hide watch expand quickreply   [Reply]
Post 'em here.
I love matrices. They're so bloody easy.
Pic unrelated
3 posts and 2 images omitted. Click Reply to view.
>> No. 3343
If they're so easy, prove the existence of jordan normal form
>> No. 3380
Fundamental Theorem of Calculus #1
>> No. 3937
Integrations of any kind.


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3685 No. 3685 hide watch expand quickreply   [Reply]
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>> No. 3924
>>3686
That's not middle school work! I learned that back in 10th grade!! High school work!!
>> No. 3925
That's not middle school work!
>> No. 3936
i = sqrt(-1)


File: 125859234580.jpg-(24.39KB, 424x253, lol.jpg)
3933 No. 3933 hide watch quickreply   [Reply]
A 20-g bullet moving at 1000 m/s is fired through a 1-kg block of wood emereging at a speed of 100 m/s (the block's velocity only.) What is the kinetic energy of the block that results from teh collision if the block had not been moving prior to the collision and was free to move ?


ans: .016 KJ

i need to know how to do the work.
>> No. 3934
AJ?
>> No. 3935
Is there a chance you're an OSU student? A lot of the freshman physicists are asking these questions right now.

By conservation of momentum,

.02kg * 1000 m/s + 1kg * 0 m/s = .02kg * 100 m/s + 1kg * v_block

Solve for v_block.

Kinetic energy is given by

Ke = .5 m v^2 = .5 * 1 kg * (v_block)^2

There you go!
>> No. 3941
Just so you know, this is a bit more /sci/ than /calc/, although there is math involved.


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3928 No. 3928 hide watch quickreply   [Reply]
ok....so this equation has been giving me some trouble...im trying to complete a review sheet so i can be ready for this test i have coming up...but this equation i cant really seem to figure out what im supposed to do....mostly its the fraction that trips me up....the answer to the equation is supposedly "3y^12 over 4x^6"....i just cant seem to get that answer....can someone take me through the steps of solving this equation? any help would be really appreciated...
>> No. 3929
File: 125851870890.gif-(2.00KB, 236x116, CodeCogsEqn.gif)
3929
That's not an equation. Here's your solution, nonetheless.

The basic idea is to take all of the powers, first. Then, because they're all multiplications, you can just sum the exponents to get the answer.
>> No. 3931
wow. i didnt even know about coefficients to the negative power meaning 1 over the coefficient to the power....thank you soo much...you saved me many headaches...
>> No. 3932
You can remember intuitively this way: an exponentiation is at its heart just a repeated multiplication. One would think that the opposite of that would then be a repeated division.


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3900 No. 3900 hide watch expand quickreply   [Reply]
What the hell is a bona fide number and why is zero a bona fide number?
3 posts omitted. Click Reply to view.
>> No. 3922
>>3919
you are wrong its 0+0i
>> No. 3923
>>3922

That's a complex number. He was talking about imaginary numbers.
>> No. 3926
>>3919 http://en.wikipedia.org/wiki/Field_(mathematics) I hope you know what a field is now. The real numbers are field. Even rational numbers are a field. Maybe you meant 'plane'?


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